Answer:
See Explanation
Explanation:
Given
See attachment for graph
Required
A situation that can be modeled by the graph.
The prompt and the response are as follows:
The type of function:
It is a linear function
The variables modeled in the function
The variables are x and y
The domain and the range
From the graph, we can see that x and y values are not limited to any constraints.
So, the domain and the range are:


Question that could be

The graph could be used to predict y value, given the x value.
Take for instance, find y when x = 10
The answer can be handpicked directly from the graph. However, the best way is to calculate the graph equation, first.
So, we have:
Pick any two points on the line of the graph


Calculate the slope (m)




The equation of the graph is:

So, we have:


Expand

To solve for y when x = 10;


