Question

1. For each of the following formulas:

1) if ionic, write the formulas of the ions; if covalent, draw the Lewis structure
2) For each covalent compound, describe the electronic and molecular geometry
3) For each covalent compound, describe the hybridization of the central atom
4) Name each compound, except the organic one.
5) How many sigma and how many pi bonds does each compound have?
MnSO4 CH3NH2 PCl5 O2 LiF

Answer 1

See Explanation

Step-by-step explanation:

The ionic compounds are; MnSO4 and LiF

The covalent compounds are; CH3NH2, PCl5 and O2

1) The formulas of the ions are;

MnSO4 - Mn^2+ SO4^2-

LiF - Li^+ F^-

The structure of each of the three covalent molecules is shown in the images attached to this answer.

2) CH3NH2 - Has a tetrahedral molecular geometry and electronic geometry

PCl5 - Has a trigonal bipyramidal molecular geometry and electronic geometry

O2 - Has a linear molecular geometry and electronic geometry.

3) CH3NH2 is sp3 hybridized

PCl5 is sp3d hybridized

O2 - is sp2 hybridized

4) MnSO4 - Manganese II sulphate

PCl5 - Phosphorus pentachloride

O2 - Oxygen molecule

LiF- Lithium fluoride

5) PCl5 - Five sigma bonds and no pi bond

CH3NH2 - 6 sigma bonds and no pi bond

O2 - 1 sigma bond and 1 pi bond