Answer:
1.46755 Joules
Step-by-step explanation:
Applying,
E = 1/2ke²......................... Equation 1
Where E = Elastic potential energy of the spring, k = spring constant, e = extension
From the question,
Gieven: k = 559 N/m, e = (0.14-0.07) meters = 0.07 meters
Substitute these values into equation 1
E = 1/2(599×0.07²)
E = 2.9351/2
E = 1.46755 Joules