Question

Una recta atraviesa el punto (8, -1) y tiene una pendiente igual a 5/4.

Escribir una ecuación en forma pendiente intersección para esta recta.

Answer 1

y = (5/4)x - 11

Explanation:

Use y = mx + b as your starting point. This becomes y = (5/4)x + b.

Substitute 8 for x and -1 for y and solve for b:

-1 = (5/4)(8) + b, or

-1 = 10 + b.

Then b must be -11, and the desired equation is

y = (5/4)x - 11