Question

Solve using the Quadratic Formula
5x2-3x-7=0
A)
B)
C)
D)

Answer 1

C)
`\displaystyle x=(3 \pm √(149))/(10)`

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Standard Form: ax² + bx + c = 0
• Quadratic Formula:
  `\displaystyle x=(-b \pm √(b^2-4ac))/(2a)`

Explanation:

Step 1: Define

Identify

5x² - 3x - 7 = 0

↓

a = 5, b = -3, c = -7

Step 2: Solve for x

1. Substitute in variables [Quadratic Formula]:
   `\displaystyle x=(3 \pm √((-3)^2-4(5)(-7)))/(2(5))`
2. [√Radical] Evaluate exponents:
   `\displaystyle x=(3 \pm √(9-4(5)(-7)))/(2(5))`
3. [√Radical] Multiply:
   `\displaystyle x=(3 \pm √(9+140))/(2(5))`
4. [√Radical] Add:
   `\displaystyle x=(3 \pm √(149))/(2(5))`
5. [Fraction] Multiply:
   `\displaystyle x=(3 \pm √(149))/(10)`