Question

Find the zeros of the function. Enter the solutions from least to greatest.

f(x) = (x + 2)^2 – 64
lesser x =
greater x =

Answer 1

6 & -10

Explanation:

Given :

• f(x) = (x+2)² - 64

And we need to find the Zeroes of the given function .For that equate the polynomial with 0 , we have ,

`:\implies` f(x) = 0

`:\implies` ( x + 2 )² - 64 = 0

`:\implies` ( x + 2)² = 64

`:\implies` ( x + 2 ) = √64

`:\implies` ( x + 2) = ± 8

`:\implies` x = -2 ±8

`:\implies` x = -10 , 6

Hence the value of 6 and -10 .