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Find the zeros of the function. Enter the solutions from least to greatest.

f(x) = (x + 2)^2 – 64
lesser x =
greater x =

1 Answer

3 votes

Answer:

6 & -10

Explanation:

Given :

  • f(x) = (x+2)² - 64

And we need to find the Zeroes of the given function .For that equate the polynomial with 0 , we have ,


:\implies f(x) = 0


:\implies ( x + 2 )² - 64 = 0


:\implies ( x + 2)² = 64


:\implies ( x + 2 ) = 64


:\implies ( x + 2) = ± 8


:\implies x = -2 ±8


:\implies x = -10 , 6

Hence the value of 6 and -10 .

User Mijamo
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