Question

Write the equation given the point 4,2 and slope 1/2

Answer 1

Hello.

We have a point that the line passes through and its slope.

Let's write the equation in Point-Slope Form:

y-y₁=m(x-x₁)

In this case,

y₁=2

m=
`\displaystyle(1)/(2)`

x₁=4

Plug in the values:

`\mathrm{y-2=\displaystyle(1)/(2) (x-4)}`

This is point-slope form. Now, what about Slope-Intercept?

First, we should distribute
`\displaystyle(1)/(2)`:

`\mathrm{y-2=\displaystyle(1)/(2) x-2}`

Add 2 to both sides:

`\mathrm{y=\displaystyle(1)/(2) x-2+2}`

Simplify:

`\mathrm{y=\displaystyle(1)/(2) x}`

I hope it helps.

Have a nice day.

`\boxed{imperturbability}`

Answer 2

Explanation:

Slope intercept form: y = mx + b

here, m is the slope and b is the y-intercept.

`y=(1)/(2)x+b`

The line passes through the point(4,2)

.Plugin these x ad y values in the above equation to find 'b'

`2= (1)/(2)*4+b\\\\\\2=2+b\\\\b = 2 - 2`

b = 0

Equation of the line :

`y =(1)/(2)x`