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For 11.20 kg of a magnesium-lead alloy of composition 30 wt% Pb-70 wt% Mg, is it possible, at equilibrium, to have α and Mg2Pb phases having respective masses of 7.39 kg and 3.81 kg? If so, what will be the approximate temperature of the alloy? If such an alloy is not possible, explain why.

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Answer:

Maximum concentration for Pb is only 41%. we get 64.3% which exceeds the maximum concentration. Therefore it is not possible.

Step-by-step explanation:

let's first determine the mass fraction of the phases as follows


W_(a)=\frac{m_(a) }{m_(a)+m_{p_(g2)p_(b) } }

Given that masses are
m_(a)=7.39kg and
m_{p_(g2)p_(b) }=3.81kg

Thus,
W_(a) =(7.39)/(7.39+3.81)=0.659


W_{M_(g2Pb) } =1-W_(a)=1-0.659=0.341

Now determine the concentration


W_(a)=(C_(0)-C_(a) )/(C_(b)-C_(a) )

At 81% PB and 70% Pb only point at which
M_(g2Pb) exists, we can solve


0.659=(70-81)/(C_(b)-81 )


C_(b)=64.3%

Refer text book page no. 326, figure 9.20, from figure we can say maximum concentration for Pb is only 41%. we get 64.3% which exceeds the maximum concentration.

User Abdul Malik
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