Look at the attachment Simplified it too pls take it seriously

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38 votes

Look at the attachment
Simplified it too
pls take it seriously

2.1k points

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13 votes

$\\ \rm\rightarrowtail (sin(180+A)+2cos(180+A).cos(A-180))/(2cos^2(360+A)-cos(-A))$

$\\ \rm\rightarrowtail (-sinA+2(cos^2A-sin^2A))/(2cos^2A-cosA)$

$\\ \rm\rightarrowtail (-sinA+2cos^2A-2sin^2A)/(cosA(2cosA-1))$

$\\ \rm\rightarrowtail (-sinA+2-2sin^2A-2sin^2A)/(cosA(2cosA-1))$

$\\ \rm\rightarrowtail (-sinA-4sin^2A)/(cosA(2cosA-1))$

$\\ \rm\rightarrowtail (-sinA(4sinA-1))/(cosA(2cosA-1))$

$\\ \rm\rightarrowtail -tanA\left((4sinA-1)/(2cosA-1)\right)$

Frin answered Jul 13, 2023

by Frin

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