Question

It took 20.0 mL of NaOH to neutralize 25 mL of 0.50 M HCl. What is the molarity of the base?

Answer 1

5/8 M

Step-by-step explanation:

NaOH + HCl ====> NaCl + H2O

in 25 mL of 0.5M acid, we have 1/80 Mol of HCl

it mean we must have 1/80 Mol of NaOH.

20 mL = 1/50 L

(1/80)Mol / (1/50)L = 5/8 M