Question

Look at the attachment
Simplified it too
pls take it seriously ​

Answer 1

`\\ \rm\rightarrowtail (sin(180+A)+2cos(180+A).cos(A-180))/(2cos^2(360+A)-cos(-A))`

`\\ \rm\rightarrowtail (-sinA+2(cos^2A-sin^2A))/(2cos^2A-cosA)`

`\\ \rm\rightarrowtail (-sinA+2cos^2A-2sin^2A)/(cosA(2cosA-1))`

`\\ \rm\rightarrowtail (-sinA+2-2sin^2A-2sin^2A)/(cosA(2cosA-1))`

`\\ \rm\rightarrowtail (-sinA-4sin^2A)/(cosA(2cosA-1))`

`\\ \rm\rightarrowtail (-sinA(4sinA-1))/(cosA(2cosA-1))`

`\\ \rm\rightarrowtail -tanA\left((4sinA-1)/(2cosA-1)\right)`