Question

a box of mass 4kg slides on the horizontal surface with kinetic frictional force of 8N. what coefficient of friction between the box and horizontal surface​

Answer 1

ų=0.8

Step-by-step explanation:

F=mg

F=4×9.81=39.24N

Ff=Fn-F

=39.24-8=31.24

ų=Ff÷Fn

=31.24÷39.24

=0.8