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Algebraic expressions x+2/x2+x-3/x2-x-2 find the l.c
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User Fredcrs
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1 Answer

2 votes

Answer:

= x^2-3x-4/x(x+1)(x-2)

Explanation:

x+2/x2+x - 3/x2-x-2

=x+2/x(x+1) - 3/x^2-x-2

=x+2/x(x+1) - 3/x^2-2x+x-2

= x+2/x(x+1) - 3/x(x-2)+1(x-2)

= x+2/x(x+1) - 3/(x+1)(x-2)

Find the LCM

= (x+2)(x-2)- (3x)/x(x+1)(x-2)

= (x+2)(x-2)- (3x)/x(x+1)(x-2)

= x^2-4-3x/x(x+1)(x-2)

= x^2-3x-4/x(x+1)(x-2)

User Seniorbenelli
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