Answer:
tan2θ = 4√2/7
Explanation:
Given sin theta=1/3 and 0 < theta< π/+
Required
tan 2 theta
tan2 theta = 2tanθ/1-tan²θ
Get tan θ
sinθ = opp/hyp
adj = √3²-1²²
adj = √9-1
adj = √8
tanθ = opp/adj = 1/2√2
tan2 theta = 2(1/2√2/1-(1/2√2)²
tan2θ = 1/√2/1-1/8
tan2θ = 1/√2/7/8
tan2θ = 8/7√2
Rationalize
tan2θ = 8√2/14
tan2θ = 4√2/7