Question

Can some one find the vertex for g(x)8x^2-14x+3 Using decimals if necessary

Answer 1

`x_(v)`Answer:

The vertex of an up - down facing parabola of the formy = ax" + bx + c is xy =

The parabola params are:

a = 8, b = -14, c =3

`x_(v)=b/2a`

`x_(v)`=-(-14)/2·8

simplify

`x_(v)`=-(-14)/2·8

`x_(v) = 7/8`

Plug in
`x_(v)`=7/8to find the
`y_(v)` value

`y_(v)`= -25/8

Therefore the parabola vertex is

(7/8 , -25/8)

If a < 0, then the vertex is a maximum value

If a > 0, then the vertex is a minimum value

a = 8

Minimum(7/8 , -25/8)