Question

1. A volume of 120.0 liters of a gas is prepared at a pressure of 400.0 mm Hg and a temperature

100.0 °C. The gas is placed into a tank under high pressure. When the tank cools to 10.0°C,
the pressure of the gas is 20.0 mm Hg. What is the volume of the gas?

Answer 1

`V_2=2487.9L`

Step-by-step explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the final volume by using the combined ideal gas:

`(P_2V_2)/(T_2)=(P_1V_1)/(T_1)`

In such a way, by solving for the final volume, V2, we obtain:

`V_2=(P_1V_1T_2)/(P_2T_1) \\\\`

Now, by plugging in the pressures, temperatures in Kelvins and initial volume, we will obtain:

`V_2=((400.0mmHg)(120.0L)(283.15K))/((20.0mmHg)(273.15K))\\\\V_2=2487.9L`

Regards!