Explanation:
For y = 2^x:
f(-3) = 2^-3. f(-2) = 2^-2. f(-1) = 2^-1
= 1/8 = 1/4. =1/2
f(0) = 2^0 f(1) = 2^1. f(2) = 2^2
= 1 = 2. =4
f(3) = 2^3
=8
For 3y = 7x + 3, y= (7x+3)/3
f(-3) = [7(-3)+3] / 3. f(-2) = [7(-2)+3] / 3
= -6. = -11/3
f(-1) = [7(-1)+3] / 3. f(0) = [7(0)+3] / 3
= -4/3 = 1
f(1) = [7(1)+3] / 3. f(2) = [7(2)+3] / 3
= 10/3 = 17/3
f(3) = [7(3)+3] / 3.
= 8
point of intersection, where y=2^x and 3y = 7x + 3 has the same x and y coordinate
Answer: (0,1) and (3,8)