Question

HELP DUE IN 15 MINS!

Write the equation of a circle that has a center of (-3, 4) and goes through the point (2, 1).

Answer 1

Explanation:

You can find the left side of the equation for a circle easily enough. It's r^2 that's the problem. It is on the right.

Left Side

(x + 3)^2 + (y - 4)^2 = r^2

Right Side.

x1 = - 3

x2 = 2

y1 = 4

y2 = 1

Use the distance formula to get r^2

r^2 = (x2 - x1)^2 + (y2 - y1)^2

r^2 = (2 - - 3)^2 + (1 - 4)^2

r^2 = 5^2 + (-3)^2

r^2 = 25 + 9

r^2 = 34

Answer

(x + 3)^2 + (y - 4)^2 = 34