Answer:
The answer is "208 mL".
Step-by-step explanation:
![C_1 = 25\% \ (m)/(v)\\\\C2 = 10\% \ (m)/(v)\\ \\V_1= 520\ \ mL\\\\V_2=?](https://img.qammunity.org/2022/formulas/chemistry/college/4ivlr1p8649pqrhijypbhz4ubve2469ysc.png)
In dilutions of different concentration, its initial volume for glucose solution V1 can be obtained by using the following formula, i.e.
![\to C_1V_1 = C_2V_2\\\\\to V_1 = (C_2V_2)/(C_1) \\\\= (10 * 520 )/( 25)\\\\ = 208 \ mL](https://img.qammunity.org/2022/formulas/chemistry/college/fh7vo1fyc6adyf4mbmelmtjy0rwriv9pmz.png)
The solution of 520 mL
final glucose solution thus requires 208 mL of glucose solution of
.