1 term= 5
10 terms = 50
16+ (55-1)5
16+54x5
54x5= 270
270+16=286
The 55th term would be 286
Answer:
286
Explanation:
Use term formula for +/-
Tn = a + (n-1)d
n= number of term
a= first number in sequence
d= difference between each number
T55 = 16 + (55-1)5
T55 = 16 + 270
=286
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