Question

A chemist must dilute 61.9 mL of 548. nM aqueous sodium carbonate (Na2CO3) solution until the concentration falls to 484. nM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Round your answer to 3 significant digits.

Answer 1

The final volume will be "70.08 mL".

Step-by-step explanation:

The given values are:

Molar mass,

M1 = 548 nM

or,

=
`5.48* 10^(-7) \ M`

M2 = 484 nM

or,

=
`4.84* 10^(-7) \ M`

Volume,

V1 = 61.9 mL

V1 = ?

By using the expression, we get

⇒
`M1* V1=M2* V2`

or,

⇒
`V2=(M1* V1)/(M2)`

By substituting the values, we get

`=(5.48* 10^(-7)* 61.9)/(4.84* 10^(-7))`

`=(339.212)/(4.84)`

`=70.08 \ mL`