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An oscillating LC circuit consisting of a 1.0 nF capacitor and a 3.0 mH coil has a maximum voltage of 3.0 V. What are (a) the maximum charge on the capacitor, (b) the maximum current through the circuit, and (c) the maximum energy stored in the magnetic field of the coil

User Sumanta
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1 Answer

1 vote

Answer:


E=4.5*10^-^9J

Step-by-step explanation:

From the question we are told that:

Capacitor
C=1.0nf

Induction
I=3.0mH

Voltage
V=3.0

Generally the equation for Max charge on Capacitor is mathematically given by


Q_(max)=C*V


Q_(max)=1*10^(-9)*3


Q_(max)=3*10^(-9)C

Generally the equation for Energy in magnetic field of the coil is mathematically given by

Since

Energy stored in capacitor = Energy in magnetic field of the coil

Therefore


E = (1/2)* C * V^2


E= 0.5 * 1*10^(-9) *3^2


E=4.5*10^-^9J

User AnnW
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