Answer:
(95.215 ; 100.785)
(95 ; 101) (nearest whole number)
Explanation:
To obtain the confidence interval :
Mean ± margin of error
Mean = 98 hours
Margin of Error = Tcritical * (s/√n)
samole standard deviation, s = 5.6 hours
df = n - 1 = 18 - 1 = 17
Tcritical at (0.05, df = 17) = 2.110
Hence ;
Margin of Error = 2.110 * (5.6/√18) = 2.785
Confidence interval :
98 ± 2.785
Lower boundary = 98 - 2.785 = 95.215
Upper boundary = 98 + 2.785 = 100.785
(95.215 ; 100.785)