Answer:
4.47
Step-by-step explanation:
Given data
vector 1 = 2m/s
vector 2= 4 m/s
The expression for the magnitude of two vectors is
|a| = √v1^2+ v2^2
substitute
|a| = √2^2+ 4^2
|a| = √4+ 16
|a| = √20
|a| = 4.47
Hence the magnitude of the two vectors is 4.47