Question

A student weighs out a 6.04 g sample of , transfers it to a 100. mL volumetric flask, adds enough water to dissolve it and then adds water to the 100. mL tick mark. What is the molarity of chromium(III) sulfate in the resulting solution

Answer 1

"0.1540 M" is the correct answer.

Step-by-step explanation:

The given values are:

Mass of sample,

M = 6.04 g

Volume,

V = 100 mL

or,

= 100×10⁻³ L

Molar weight of Chromium(III) sulfate

MW = 392.16 g/mol

Now,

The molarity will be:

=
`(M)/(MW* V)`

By putting the values, we get

=
`(6.04)/(392.16* 100* 10^(-3))`

=
`(6.04)/(39.216)`

=
`0.1540 \ M`