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The current altitude of the plane is 15400 feet above the ground and the plane's horizontal distance to the airport is 200000 miles away. What angle of depression must the pilot make on his descent in order to safely land on the runway>

User Sarang
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1 Answer

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Answer:

0.441°

Explanation:

tan = 1540/200000

tan = 0.0077

tan-1(0.0077) = 0.441

angle of depression is 0.0441°

User Olisa
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