Question

2. Given the following balanced chemical equation: 3ZnO + 2Li3N

-->
Zn3N2 + 3Li20
If 3.14 g of ZnO reacts with 3.14 g of Li3N,
a. Identify the limiting reactant.
b. Identify the reactant in excess.
c. How many grams of Zn3N2 are formed?
d. How many grams of the excess reactant are needed for the reaction?
e. How many grams of the excess reactant are left at the end of the reaction?

Answer 1

Answer: For question, C. 224.1534

Step-by-step explanation:

1 mole is equal to 1 moles Zn3N2, or 224.1534 grams.