Question

A solid steel ball is thrown directly downward, with an initial speed 7.30 m/s, from the top of a building at a height of 29.5 m. How much time in seconds does it take before the ground?

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Answer 1

h=vi.t+1/2gt²

29.5 = 7.3t+1/2 x 9.8 x t²

4.9t²+7.3t-29.5=0

abc formula⇒ t = 1.82 s

Answer 2

1.82 seconds

Step-by-step explanation:

see paper for full explanation :)