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If two charged objects each have 2.5 C of charge on them and are located 100 m apart, how strong is the electrostatic force between them?

User Designosis
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1 Answer

2 votes

Answer:

5.619×10⁶ N

Step-by-step explanation:

Applying,

F = kqq'/r²................... Equation 1

Where F = electrostatic force between the charges, k = coulomb's constant, q = first charge, q' = second charge, r = distance btween the charges

From the questiion,

Given: q = 2.5 C, q' = 2.5 C, r = 100 m

Constant: 8.99×10⁹ Nm²/C²

Substitute these values into equation 1

F = (2.5×2.5×8.99×10⁹)/100²

F = 56.19×10⁵

F = 5.619×10⁶ N

User JCWong
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