Question

Find the measure of the arc TDB in the circle P shown below:

Answer 1

`\huge{ \mathfrak{  \underline{ Answer \:  \:  ✓ }}}`

The Angle formed by an arc on the centre of the circle is double the angle made by the same arc on the circumference of the circle.

So,

`\boxed{ \mathrm{ \angle TDB = (1)/(2) \angle TPB }}`

• 
  `\mathrm{\angle TDB = (1)/(2) * 90 \degree}`

• 
  `\mathrm{\angle TDB =45 \degree }`

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