Question

A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. Using this estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical store? .78 .50 .28 .22

Answer 1

`p' = 0.22`

Explanation:

Given

`p = (78)/(100)`

Required

Probability that a
`customer` does
`not` live
`within`
`50` miles

To do this, we make use of complement rule;

Which states that:

`p + p' = 1`

Make p' the subject

`p' = 1 - p`

So, we have:

`p' = 1 - (78)/(100)`

Express fraction as decimal

`p' = 1 - 0.78`

`p' = 0.22`