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If 2.18 grams of Br2 react with excess KI, how many grams of KBr are formed? Br2 + 2 K1 - 12 +2 KB

User Dulgan
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1 Answer

4 votes

Answer:

2.18 grams of Br2 reacts to produce 3.25 grams of KBr

Step-by-step explanation:

The balanced equation is

2 KI + Br2 → 2 KBr + I2

2 moles of KI and 1 mole of Br2 reacts to produce two molecules of KBr

Mass of two moles of KI = 2 * 166 grams

Mass of one mole of Br2 = 159.808 grams

Mass of two moles of KBr = 2* 119 grams

Thus, 159.808 grams of Br2 reacts to produce 2* 119 grams of KBr

2.18 grams of Br2 reacts to produce {(2* 119)/ 159.808} * 2.18 grams of KBr

2.18 grams of Br2 reacts to produce 3.25 grams of KBr

User Raman Branavitski
by
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