Question

A gas has a volume of 45.0 mL and a pressure of .98 atm. If the pressure increased to 2.1 atm and the temperature remained the same, what would be the new volume?

Answer 1

Answer: The new volume is 95.45 mL.

Step-by-step explanation:

Given:
`V_(1)` = 45.0 mL,
`P_(1)` = 0.98 atm

`P_(2)` = 2.1 atm,
`V_(2)` = ?

According to Boyle's law, at constant temperature the pressure of a gas is inversely proportional to its volume.

Therefore, formula used to calculate the new volume is as follows.

`(P_(1))/(V_(1)) = (P_(2))/(V_(2))`

Substitute the values into above formula as follows.

`(P_(1))/(V_(1)) = (P_(2))/(V_(2))\\(0.98 atm)/(45.0 mL) = (2.1 atm)/(V_(2))\\V_(2) = 95.45 mL`

Thus, we can conclude that the new volume is 95.45 mL.