Question

Calculate the new temperature when a container of

gas has a pressure of 795 mm Hg at 273 K and the
pressure is lowered to 358 mm Hg.
(Gay Lussac's Law) P1T2/P2T1

- 0.00165
- 246
- 123
- 606

Answer 1

Answer: The new temperature of container is 123 K.

Step-by-step explanation:

Given:
`P_(1)` = 795 mm Hg,
`T_(1)` = 273 K

`P_(2)` = 358 mm Hg,
`T_(2)` = ?

Formula used to calculate the new temperature is as follows.

`(P_(1))/(T_(1)) = (P_(2))/(T_(2))`

Substitute the values into above formula as follows.

`(P_(1))/(T_(1)) = (P_(2))/(T_(2))\\(795 mm Hg)/(273 K) = (358 mm Hg)/(T_(2))\\T_(2) = 123 K`

Thus, we can conclude that the new temperature of container is 123 K.