Question

An opaque bag contains 5 blu marbles, 4 green marbles, and 3 red marbles. If two consecutive marbles are drawn without replacement what is the probability that the first one will be red and the second one will be blue?

Answer 1

Probability[Choosing red and blue consecutive] = 5/44

Explanation:

Given:

Number of blue marble = 5

Number of green marble = 4

Number of red marble = 3

Find:

Probability[Choosing red and blue consecutive]

Computation:

Probability of red marble = Number of red marble / Total marble

Probability of red marble = 3 / [5 + 4 + 3]

Probability of red marble = 3 / 12

Probability of red marble = 1/4

Probability of next blue marble = Number of blue marble / [Total marble - 1]

Probability of next blue marble = 5 / [Total marble - 1]

Probability of next blue marble = 5 / [12 - 1]

Probability of next blue marble = 5 / 11

Probability[Choosing red and blue consecutive] = Probability of red marble x Probability of next blue marble

Probability[Choosing red and blue consecutive] = [1/4][5/11]

Probability[Choosing red and blue consecutive] = 5/44