Answer:
Assume that the two digits are x and y (x is at ones position and y is at tens position)
if we subtract the digit of a two digit number, we get 4.
this means,
x-y=4 ..................... (1)
if we interchange the digits of the number and subtract the new number from the original number we get 44.
this means,
old no. 10y+x
new no. 10x+y
10y+x-(10x+y)=44
10y+x-10x-y=44
9y-9x=44 ........................... (2)
solve the two equations:
id these two equations are solved, we get no solution.
meaning, such a number with these given conditions do not exist
Explanation: