182k views
0 votes
Cooper invested $3,100 in an account paying an interest rate of 2%

compounded quarterly. Robert invested $3,100 in an account paying an
interest rate of 3 % compounded continuously.After 12 years, how much
more money would Robert have in his account than Cooper, to the nearest
dollar?

2 Answers

7 votes

Answer:

$139

Explanation:

User Eunsun
by
4.0k points
3 votes

Answer:

Rounded to the nearest dollar, Robert will have $ 505 more than Cooper on his account.

Explanation:

Given that Cooper invested $ 3,100 in an account paying an interest rate of 2% compounded quarterly, while Robert invested $ 3,100 in an account paying an interest rate of 3% compounded continuously, to determine, after 12 years, how much more money would Robert have in his account than Cooper to the nearest dollar, the following calculation must be made:

Compound interest formula: Initial x (1 + interest / composition) ^ composition x years

Continuous compound interest formula: Initial x exp ^ (interest x years)

Cooper:

3,100 x (1 + 0.02 / 4) ^ 12x4 = X

3,100 x (1 + 0.005) ^ 48 = X

3,100 x 1,005 ^ 48 = X

3,100 x 1,270 = X

3,938.51 = X

Robert:

3,100 x 2.71828182845904 ^ (3x12) = X

4,443.32 = X

4,443.32 - 3,938.51 = X

504.51 = X

Therefore, rounded to the nearest dollar, Robert will have $ 505 more than Cooper on his account.

User Marvi
by
3.7k points