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HELPPPP PLEASEEE IM BEGGING SOMEONE PLEASE PLEASE HELP

HELPPPP PLEASEEE IM BEGGING SOMEONE PLEASE PLEASE HELP-example-1

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Given:

The figure of a rhombus QRST.

To find:

A. The value of x.

B. The measure of angle RQP.

Solution:

A. We need to find the value of x.

We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.


m\angle RPS=90^\circ [Right angle]


(5x+15)^\circ=90^\circ


(5x+15)=90


5x=90-15


5x=75

Divide both sides by 5.


x=(75)/(5)


x=15

Therefore, the value of x is 15.

B. We need to find the measure of angle RQP.

From the given figure, it is clear that


m\angle RQP=(2x+3)^\circ

Putting
x=15, we get


m\angle RQP=(2(15)+3)^\circ


m\angle RQP=(30+3)^\circ


m\angle RQP=33^\circ

Therefore, the measure of angle RQP is 33 degrees.

User Dlowe
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