Question

20 points plz help i dont really understand how to do this

my grades at d rn plz help lol tysm if you do < 3
. Calculate the equivalent resistance of the circuit.


c. Calculate the current through the battery.


d. How much current is passing through each resistor

Answer 1

`\huge{ \mathfrak{  \underline{ Answer} \:  \:  ✓ }}`

1. Calculate the equivalent resistance in the circuit :

In the given diagram, the resistors are in series connection,

So equivalent resistance = sum of resistance of both resistors.

`\large \boxed{R_(eq) =R_1 +R_2 }`

• 
  `R_(eq) = 480 + 360`

• 
  `R_(eq) = 840 \: ohms`

Therefore, Equivalent resistance = 840 ohms.

2. Calculate the current through the battery :

`\boxed{ \mathrm{current = (potential \: \: difference)/(resistance) }}`

• 
  `i = (120)/(840)`

• 
  `i = (1)/(7)`

• 
  `i = 0.142 \: Amperes`

Hence, current through the battery = 0.142 A

3. How much current is passing through each resistor :

Since the resistors are joined in series connection, the current flowing through each resistor will be equal = 0.142 Amperes.

___________________________

`\mathrm{ \#TeeNForeveR}`