223k views
0 votes
The function h(t)=−16t(t−7) models the height of an object at any time t after it is launched, where t is measured in seconds. After how many seconds will the object hit the ground?

User Marcbest
by
8.1k points

1 Answer

5 votes

Answer:

2.65secs

Explanation:

Give:

The function h(t)=−16t(t−7) models

the object will hit the ground at h= 0

h(t)=−16t(t−7)

0= -16t(t−7)

0= -16t^2 + 112

16t^2 = 112

t^2 = 7

t= √7

t=2.65secs

Hence, the object object hit the ground at 2.65secs

User Ashley Kilgour
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.