Question

PLS HELP

When 50.0 g of copper was reacted with 300.0 g of silver nitrate solution, 149 g of silver was obtained. What is the percent yield of silver obtained?

Answer 1

The question is about calculating the percent yield of silver from a reaction of copper and silver nitrate. To calculate the percent yield, the actual yield is divided by the theoretical yield and then multiplied by 100. The actual yield is given as 149 g of silver, but the theoretical yield is not provided in the question.

Step-by-step explanation:

The student asked about the percent yield of silver obtained when copper reacts with silver nitrate solution. To find the percent yield, we compare the actual yield to the theoretical yield using the formula:

Percent Yield = (Actual Yield / Theoretical Yield) × 100%

In this case, the actual yield is the amount of silver produced, which is 149 g. The theoretical yield would require the chemical equation and some stoichiometry calculations to determine what the expected amount of silver would be, but this information is not provided. However, if we had the theoretical yield, we could calculate the percent yield using the actual yield of 149 g of silver.

The concept of percent yield is vital for understanding the efficiency of chemical reactions and for planning reactions in a laboratory or industrial setting.

Answer 2

Percent yield of silver obtained = 78.18% (Approx.)

Step-by-step explanation:

Given:

Amount of copper = 50 gram

Amount of silver nitrate = 300 gram

Amount of silver = 149 gram

Find:

Percent yield of silver obtained

Computation:

Percentage of Silver in silver nitrate = 108[100/(108+14+48)]

Percentage of Silver in silver nitrate = 108/[100/170]

Percentage of Silver in silver nitrate = 63.53% (Approx.)

Amount of Silver produced = [63.53%][300]

Amount of Silver produced = 190.59 gram

Percent yield of silver obtained = [Amount of silver / Amount of silver produced]100

Percent yield of silver obtained = [149/190.59]100

Percent yield of silver obtained = 78.18% (Approx.)