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Whats the average rate of change of h over the interval 5 ≤ t ≤ 9?

Whats the average rate of change of h over the interval 5 ≤ t ≤ 9?-example-1

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Given:

The graph of a function.

To find:

The average rate of change of h over the interval
5\leq t\leq 9.

Solution:

The average rate of change of a function f(x) over the interval [a,b] is:


m=(f(x_2)-f(x_1))/(x_2-x_1)

So, the average rate of change of h over the interval
5\leq t\leq 9 is:


m=(h(9)-h(5))/(9-5)

From the given graph it is clear that
h(9)=7,h(5)=3. Substituting these values, we get


m=(7-3)/(9-5)


m=(4)/(4)


m=1

Therefore, the average rate of change of h over the interval
5\leq t\leq 9 is 1.

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