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How many grams of glucose (CH20) can corn grown in central Illinois make using 5.0 L of carbon dioxide gas and 2.5 L of water at 32 °C and 750 mmHg?

ground to two decimal values)

How many grams of glucose (CH20) can corn grown in central Illinois make using 5.0 L-example-1
User Ars
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5 votes

Answer:

5.9 g

Step-by-step explanation:

Step 1: Write the balanced reaction for the photosynthesis

6 CO₂ + 6 H₂O ⇒ C₆H₁₂O₆ + 6 O₂

Step 2: Calculate the moles of CO₂

We have 5.0 L of CO₂ at 32 °C (305 K) and 750 mmHg. We can calculate the moles of CO₂ using the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 750 mmHg × 5.0 L/(62.4 mmHg.L/mol.K) × 305 K = 0.20 mol

Step 3: Calculate the moles of C₆H₁₂O₆ produced from 0.20 moles of CO₂

The molar ratio of CO₂ to C₆H₁₂O₆ is 6:1. The moles of C₆H₁₂O₆ produced are 1/6 × 0.20 mol = 0.033 mol

Step 4: Calculate the mass corresponding to 0.033 moles of C₆H₁₂O₆

The molar mass of C₆H₁₂O₆ is 180.16 g/mol.

0.033 mol × 180.16 g/mol = 5.9 g

User Icyfire
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