Question

Find the value of T1 if 1 = 30°, 2 = 60°, and the weight of the object is 139.3 newtons.

A.
69.58 newtons
B.
45.05 newtons
C.
25 newtons
D.
98.26 newtons

Answer 1

69.58

Step-by-step explanation:

Answer 2

Option A (69.56 newtons) is the appropriate solution.

Step-by-step explanation:

According to the question,

On the X-axis,

⇒
`T_1Cos30^(\circ)-T_2Cos60^(\circ)=0`

or,

`T_1Cos 30^(\circ)=T_2Cos60^(\circ)`

On substituting the values, we get

`T_1* (√(3) )/(2)=T_2* (1)/(2)`

`T_1* √(3) =T_2`....(equation 1)

On the Y-axis,

⇒
`T_1Sin30^(\circ)+T_2Sin60^(\circ)=139.3 \ N`

`(T_1)/(2) +(√(3) )/(2) =139.2 \ N`

`T_1+√(3)T_2=139.2* 2`

From equation 1, we get

`T_1+√(3)* √(3)T_1 =278.4 \ N`

`T_1+3T_1=278.4 \ N`

`4T_1=278.4 \ N`

`T_1=(278.4)/(4)`

`=69.6 \ N`