Question

A pitcher claims he can throw a 0.174 kg baseball with as much momentum as a speeding bullet. Assume that a 5 g bullet moves at a speed of 1,115 m/s. What must the baseball’s speed (m/s) be if the pitcher’s claim is valid?

Answer 1

`320.4\:\mathrm{m/s}`

Step-by-step explanation:

The momentum of an object is given by
`p=mv`. Therefore, we have the following equation:

`m_(ba)v_(ba)=m_(bu)v_(bu),\\0.174\cdot v_(ba)=0.005\cdot 1115,\\v_(ba)\approx \boxed{320.4\:\mathrm{m/s}}`

*Note: it's important to convert grams to kilograms, as kilograms are the SI unit for mass