Question

What is an equation of the line that passes through the points (-2,-6) and (6,8)?

Answer 1

y=7/4x–5/2

Explanation:

You must find the slope first, let it be m

`m = (y2 - y1)/(x2 - x1) \\ = (8 - ( - 6))/(6 - ( - 2)) \\ = (14)/(8) \\ = (7)/(4)`

then insert tu the formula y=mx+c to find the c (c is the intercept of y axis) choose any point that you want. i use (6,8)

`y = mx + c \\ 8 = (7)/(4) (6) + c \\ c = - (5)/(2)`

so the equation is

`y = (7)/(4) x - (5)/(2)`