Question

Which constant number would you add to both sides of the equation in order to complete the square for the quadratic function 1 = x2 - 6x?​

Answer 1

Solution given:

equation is:

1=x²-6x

x²-6x-1=0

comparing above equation with ax²+bx+c=0

we get

a=1

b=-6

c=-1

now

constant no.
`{((b)/(2))}^(2)= {((-6)/(2))}^(2)=(36)/(4)=9`

constant required no is 9.

Answer 2

• 9

Explanation:

Identity of the square of a sum:

• (a + b)² = a² + 2ab + b²

Applied to given equation:

• 1 = x² - 6x
• 1 = x² - 2*x*3
• 1 + 3² = x² - 2*x*3 + 3²
• 1 + 9 = (x - 3)²

The added constant is 9