Question

10 points. Please help.

A balloon can hold 10 liters of a gas. If you blow up this balloon with 2 moles of oxygen gas at a pressure of 0.76 atmospheres, what is the temperature of the balloon? Pay attention to the unit of pressure used.

Answer 1

The temperature of the balloon is 46.34 K.

Step-by-step explanation:

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case:

• P= 0.76 atm
• V= 10 L
• n= 2 moles
• R= 0.082
  `(atm*L)/(mol*K)`
• T= ?

Replacing:

0.76 atm* 10 L= 2 moles* 0.082
`(atm*L)/(mol*K)` *T

Solving:

`T=(0.76 atm* 10 L)/(2 moles* 0.082(atm*L)/(mol*K))`

T= 46.34 K

The temperature of the balloon is 46.34 K.