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PH =5 and now to prepare a buffer solution what will be the proportion of ethanoic acid and sodium ethanoate
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PH =5 and now to prepare a buffer solution what will be the proportion of ethanoic acid and sodium ethanoate

User Aroldo
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1 Answer

5 votes

Answer:

CH3COONa : CH3COOH = 1.74 : 1 (required to prepare a buffer at PH = 5)

Step-by-step explanation:

Given that :

PH = 5

Calculate proportions of ethanoic acid and Sodium ethanoate to prepare Buffer solution

solution :

PH = Pka + Log ( CH3COONa / CH3COOH )

5.0 = 4.76 + Log ( CH3COONa / CH3COOH )

∴ Log ( CH3COONa / CH3COOH ) = 0.24

( CH3COONa / CH3COOH ) = 1.74

Therefore : CH3COONa : CH3COOH

1.74 : 1

User DavitS
by
5.6k points
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