Answer:
Explanation:
In this question we are given an equation that is 22x + 100 = 25x + 70. And we are asked to find the value of x .
Solution : -
![\longmapsto \:22x + 100 = 25x + 70](https://img.qammunity.org/2023/formulas/mathematics/high-school/smk43ue8ablfe454akx9qsirun82ozvvz2.png)
Step 1 : Subtracting 100 from both sides :
![\longmapsto \:22x + \cancel{100} - \cancel{100} = 25x + 70 - 100](https://img.qammunity.org/2023/formulas/mathematics/high-school/vk3xoj7ibb771kxl7t3xmb4gciqobdtymx.png)
On further calculations we get :
![\longmapsto \: 22x = 25x - 30](https://img.qammunity.org/2023/formulas/mathematics/high-school/rf65z3v4ls64zqk07th7pp92gu8i767p5t.png)
Step 2 : Subtracting 25x from both sides :
![\longmapsto \:22x - 25x = \cancel{ 25x} - \cancel{25x }- 30](https://img.qammunity.org/2023/formulas/mathematics/high-school/qao5w1awpfno1y0afwr7vhfgyz3sgm2prc.png)
On further calculations we get :
![\longmapsto \: \cancel{- }3x = \cancel{ - }30](https://img.qammunity.org/2023/formulas/mathematics/high-school/4j8zd2rsch3hj77z0cdcs3t1s04liruiv1.png)
Step 3 : Dividing with 3 on both sides :
![\longmapsto \: \frac{ \cancel{3}x}{ \cancel{3}} = \cancel{(30)/(3) }](https://img.qammunity.org/2023/formulas/mathematics/high-school/rphc0tsiwl8fvxvn3w9vx9yddqgo3z94oi.png)
On further calculations we get :
![\longmapsto \: \purple{\boxed{ \frak{x = 10}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/sh2nxfc9i5163aa4wkcqe95dxavwc67g1q.png)
- Henceforth , value of x is 10 .
Verifying : -
We're verifying our answer by substituting value of x in given equation . So ,
- 22 ( 10 ) + 100 = 25 ( 10 ) + 70
Therefore, our value for x is correct .
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